Question

6. A cottage industry produces a certain number of pottery articles in a day. It was observed
on a particular day that the cost of production of each article (in rupees) was 3 more than
twice the number of articles produced on that day. If the total cost of production on that
day was 90, find the number of articles produced and the cost of each article.​

Answer 1

Let there be x articles.

Then the production cost of each article =

$3+2x$

Total production cost =

$x(3+2x)=90$

$3x+2x2=90 \\ 2x2+3x−90=0 \\ 2x2+15x−12x−90=0 \\ 2x(x−6)+15(x−6)=0 \\ (2x+15)(x−6)=0 \\ x = 6, - \frac{15}{2}$

Answer 2

hope it helps you...

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