Physics, asked by pushpraj007, 1 month ago

6.
A current of 10 A is maintained in a conductor of
cross-section 1 cm2. If the number density of free
electrons be 9 x 1028 m-3, the drift velocity of free
electrons is
(1) 6.94 x 10-6 m/s (2) 5.94 x 10-2 m/s
(3) 1.94 x 10-3 m/s (4) 2.94 x 10-4 m/s

Answers

Answered by thisisanurag2001
0

as we know that formula

I = neAvd

10 = 9×1028× 1.6× 10^-19×10^-6×vd

find just vd over here

Similar questions