Question

6. A mercury thermometer has a bulb of volume 0.300cm3 and a stem of diameter 0.0100 cm.
the rise of mercury meniscus in the stem
en the temperature rises through 15°C. Given :
1.82 x 10 4 °C . Ignore the expansion of
Ans. 10.4 cm.
Ymercury = 1.82 x 10-4 0-1
the bulb.​

Answer 1

A mercury thermometer has a bulb of volume 0.300cm3 and a stem of diameter 0.0100 cm. The rise of mercury meniscus in the stem  is 10.4 cm when the temperature rises through 15°C.

As we know that expansion in the mercury is given as

$\Delta V = V_o \gamma \Delta T$

here we have

$V_o = 0.300 cm^3$

$\gamma = 1.82 \times 10^{-4}$

$\Delta T = 15^o C$

now we have

$\Delta V = (0.300)(1.82 \times 10^{-4})(15)$

$\Delta V = 8.19 \times 10^{-4} cm^3$

now we know that height raised by the it is given as

$h = \frac{\Delta V}{A}$

$h = \frac{8.19 \times 10^{-4}}{\pi(\frac{0.01}{2})^2}$

$h = 10.4 cm$

#Learn

Topic : volume expansion of liquid due to rise in temperature

https://brainly.in/question/13161728

Answer 2

Answer:

Explanation:

A mercury thermometer has a bulb of volume 0.300cm3 and a stem of diameter 0.0100 cm. The rise of mercury meniscus in the stem  is 10.4 cm when the temperature rises through 15°C.