Math, asked by sehajnoor3, 2 months ago


6. A motorcycle was purchased for 48000. If its value depreciates every year by 10%,
calculate the total depreciation in its value at the end of 3 years.​

Answers

Answered by bhatbhargavi06
2

Answer:

The final price after three years is Rs. 34992.

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Attachments:
Answered by tennetiraj86
12

Step-by-step explanation:

Given:-

A motorcycle was purchased for 48000. If its value depreciates every year by 10%,

To find:-

calculate the total depreciation in its value at the end of 3 years.

Solution:-

General method:-

Cost Price if a motorcycle = Rs. 48000

Depreciation value of it every year = 10%

Depreciation value in the first year

=>48000×10%

=>48000×(10/100)

=>48000/10

=>4800

The Cost price of the motor cycle =

48000-4800= Rs.43200

The depreciation value of the motorcycle at the second year.

=10% of 43200

=>43200×(10/100)

=>43200/10

=>4320

The Cost Price of the motor cycle at the end of second year = 43200-4320=Rs. 38880

The depreciation value of the motor cycle at the end of 3rd year

=>10% of 38880

=>38880×(10/100)

=>38880/10

=>3888

The Cost Price of the motor cycle at the end of third year = 38880-3888= Rs. 34992

The total depreciation in the value of motorcycle at the end of 3 years

=>4800+4320+3888

=>Rs.13008

(or)

Initial cost price- Final cost price at the end of 3rd year

=>48000-34992

=>Rs. 13008

(or)

Formula method:-

The initial cost price = 48000

Time = 3 years

depreciation = 10%

P=48000

R=10%

T=n=3

The Cost price at the end of 3 years

= P[1-(R/100)^n

=>48000[1-(10/100)]^3

=>48000[1-(1/10)]^3

=>48000[(10-1)/10]^3

=>48000[9/10]^3

=>(48000×9×9×9)/(10×10×10)

=>48000×729/1000

=>48×729

=>34992

The Cost price = Rs.34992

The depreciation value of the motor cycle at the end of three years

=>48000-34992

=>Rs. 13008

Answer:-

The depreciation value of the given motorcycle at the end of 3 years is Rs.13008

The Cost price of the given motorcycle at the end of 3 years = Rs.33992

Used formulae:-

The Price of an article is P and R% is the depreciation in its value by every year then the value of it at the end of n years = P[1-(R/100)]^n

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