Question

6.
A particle is fired vertically upward with a speed
of 9.8 km s. Find the maximum height attained
by the particle. Radius of earth=6400 km and g
at the surface = 9.8 ms 2. Consider only earth's
gravitation

Answer 1

Answer:

4950km hope it helps . . .

Answer 2

$h=5306.26\ km$ is  the maximum height attained  by the particle.

Explanation:

Given:

• velocity of the particle, $v=9800\ m.s^{-1}$

• Radius of the earth, $R=6.4\times 10^6\ m$

• gravity at the surface of the earth,  $g=9.8\ m.s^{-2}$

According to the law of energy conservation:

Total kinetic energy = total gravitation potential energy

$\frac{1}{2} m.v^2=\frac{m.g.h}{(1+\frac{h}{R}) }$

$h=\frac{R.v^2}{(2g.R-v^2)}$

$h=\frac{6.4\times 10^6\times 9800^2}{(2\times 9.8\times 6.4\times 10^6-9800^2)}$

$h=5306.26\ km$

TOPIC: Projection in gravitational field, gravitation potential energy

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