Physics, asked by gkjoshi70, 4 months ago


6. A particle moves along the X-axis in such a way that
its x-coordinate varies with time according to the equa-
tion x = 2 - 51 + 61-. The initial velocity and accelera-
tion will respectively be:

(A) 5 m/s, 12 m/s"
(B) -12 m/s, -5 m/s2
(C) 12, -5 m/s2
(D).-5 m/s, 12 m/s2​

Answers

Answered by manitaBharti
0

Answer:

The displacement is given as: y=ut+

2

1

at

2

where, u is the initial velocity and a is the acceleration

Comparing with given expression:

y=−5t+6t

2

+2

u=−5m/s, a=12m/s

2

So initial velocity is −5 m/s

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