6)A quadratic polynomial in x with real coefficients is of the form
ax^2 + bx + c, where a, b, c are real numbers with a = 0.
Formula of quadratic equation ax^2 + bx + c = 0 is
X = -b + √b^2-4ac/2a here show that b2 - 4ac is 0
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Step-by-step explanation:
if the expression has two equal roots , then the discriminant i.e b^2-4ac will be 0.
I hope you got atleast minimum solution.
the question is not so clear to answer it perfectly.
I'm sorry frnd.
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