6. A salesman travels a distance of 50 km in 2 hours and 30 minutes. How much faster, in kilometers per
hour, on an average, must he travel to make such a trip in 5/6 hour less time?
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Answer:
TIME REQUIRED
= (2 hrs _30 minutes _50 minutes)
= 1 hr 40 min.1 2/3 hrs.
therefore , required speed
=(50×3/5) km/hr
original speed =(50×2/5) km /hr
= 20 km / hr
therefore difference in speed = (30_20) km/ Hr =10 km / Hr
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