Question

6). A silver atom in a solid oscillates in simple harmonic motion in
some direction with a frequency of 1012/sec. What is the force
constant of the bonds connecting one atom with the other? (Mole
wt. of silver=108 and Avagadro number=6.02 x 1023 gm mole-1)​

Answer 1

Answer:

Time period of SHM is given by:

T=2πkm​

​

Frequency=2π1​mk​

​=1012

where m = mass of one atom

=6.02×1023108​×10−3kg

2π1​10810−3k​×6.02×1023

​

so k=7.1mN​