Question

6. A solid iron pole consists of a cylinder of height 220 cm and base diameter 24 cm, which
is surmounted by another cylinder of height 60 cm and radius 8 cm. Find the mass of the
pole, given that 1 cm of iron has approximately 8g mass. (Use A = 3.14)​

Answer 1

Answer:

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Step-by-step explanation:

1. V_1 = pi (r^2) (h) = pi (12^12) (220) = 31680 pi m^3

2. V_2 = pi (r^2) (h) = pi (8^8) ( 60 ) = 3840 pi m^3

3. V_3 = V_1 +V_2 = 31680 pi + 3840 pi = 35520 pi m^3

4. mass =  8 x 35520 pi = 284160 pi m^3

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Answer 2

Solution :-

Diameter of larger cylinder = 24cm

Radius of larger cylinder = 24/2 = 12cm

Height of the larger cylinder = 220 cm

Volume of the larger cylinder = πr²h

=> 3.14 × 12 × 12 × 220 cm³

=> 3.14 × 144 × 220 cm³

=> 99475.2 cm³

Radius of the smaller cylinder = 8 cm

Height of the smaller cylinder = 60 cm

volume of the smaller cylinder = πr²h

=> 3.14 × 8 × 8 × 60

=> 3.14 × 64 × 60

=> 12057.6 cm³

Volume of the iron pole :-

volume of smaller + volume of larger cylinder

=> 99475.2 cm³ + 12057.6 cm³

=> 111532.8 cm³

Mass in iron of 1 cm³ = 8g

Mass in iron of 111532.8 cm³ = 111532.8 × 8

=> 892,262.4 gm

=> $\frac{892,262.4}{1000}$

=> 892.26 kg

Hence, The mass of the iron pole is 892.26kg.

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