9. What would be the pH of an aqueous solution of sulphuric acid which is
5 x 10^-5 mol li - in concentration?
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Answer:
pH=4.3
Explanation:
H2SO4 (aq)
pH=-log(base10)[H]+
[H]+=5×10^-5molarity or mol/dm³
pH=-log(base10)(5×10^-5)
pH=4.3
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