6. A train moving with a velocity of 20 m s' is brought
to rest by applying brakes in 5 s. Calculate the retardation
Answers
Given, a train is moving with a velocity of 20 m/s or Initial velocity = 20 m/s
And, The train is brought to rest by applying breaks in 5 s. Which means final velocity = 0m/s and time taken = 5 s
Now, we need to find the Retardation.
By First law of motion,
⇒ v = u + at , where
- v = Final Velocity
- u = Initial Velocity
- a = Acceleration
⇒ 0 = 20 + 5a
⇒ 5a = -20
⇒ a = -4 m/s²
Hence, retàrdation is 4 m/s²
Some Information :-
◉ Retàrdation is known as negative acceleration.
◉ Acceleration is the rate of change of velocity per unit time.
Other Equations of Motion :-
◉ h = ut + (at²)/2 , where
- h = Height reached
- u = Initial velocity
- v = Final Velocity
- a = Acceleration
- t = Time taken
◉ 2as = v² - u² , where
- s = Distance travelled
Answer:
Retardation =4m/s^2
Explanation:
u = 20m/s
v = 0m/s
t = 5s
a = ?
using first equation;
v = u + at
0 = 20+a*t
-20 = 5a
5a = -20
a = -4m/s^2
Hope it helps
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