6) A wire is 1m long, 0.22mm diameter and of resistance 10 ohm. calculate the resistivity
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Answer:
the resistivity of the conductor is 3.799× 10^-7 ohm- m
Explanation:
here , it is Given that:
l=1m ,d=0.22mm=>r=0.11mm and R=10 ohm
by using the formula,
R= p౹/ A
= p౹/ πr²
therefore, p= Rπr²/l
= 10× 3.14×( 0.11× 10 -³)²
= 10× 3.14× 0.11×0.11× 10^ -6
= 0.3799× 10^-6
= 3.799× 10^-7 ohm- m
hence, the resistivity of the conductor is 3.799× 10^-7 ohm- m
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