Question

6. ABCD is a square of side x cm. PQRS is a rectangle of dimensions (x + 3) cm by (x - 3) cm. (a) Show that ABCD and PQRS have equal perimeters. Find area of PQRS (6)​

Answer 1

Answer:

ANS = x^2-9 sq units this is the area of rectangle

Step-by-step explanation:

firstly

square perimeter = 4*x = as 4 × the side (x)

now,

rectangle perimeter is = 2(l+b)

thus , 2(x+3+x-3)

which is 2(2x)=4x

so perimeter of square abcd= perimeter of rectangle pqrs

also area = l*b = (x+3)(x-3) = from a2-b2 = we get x^2-9 as ans

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