Question

6. Afirst order reaction which is 30% complete in 30 minutes has a half-life period of:

Answer 1

Answer:

Hey Dear,

● Answer -

T = 58.28 min

● Explanation -

As we know,

t = (1/k) ln(a / a-x)

Here,

30 = (1/k) ln(100 / 100-30)

k = ln(10/7) / 30

k = 0.3567 / 30

k = 0.01189

Half life of the reaction is calculated as -

T = 0.693 / k

T = 0.693 / 0.01189

T = 58.28 min

Hence, half life of the reaction is 58.28 min.

Hope this helped you.