Question

6. Amit and Varun can do a piece of work in 15 days. Varun alone can do1/5 of the work in 5 days. In how many days Amit alone can do the whole work?

《 Please answer it fast ☆ 》 ​

Answer 1

Answer:

let ,Amit can do work in x days.

Step-by-step explanation:

so,they both can do work =15 days

total work =Amit work +Varun work

so,15= X+1/5

X=15-1/5

X= 75-1/5

X=74/5

hence ,Amit alone can do work in 74/5 days .(ans)

Answer 2

Answer:

Question:

Amit and Varun can do a piece of work in 15 days. Varun alone can do1/5 of the work in 5 days. In how many days Amit alone can do the whole work?

Answer:

GIVEN:

Amit and Varun together work - in 15 days.

one day work of both = 1 / 15th

To Find:

Amit alone can do the whole work - ?

Step by Step:

Let the Varun can do work in x days

✑ Work done by Varun alone in 1 day 1 / x  -(i)

✑Work done by Varun alone in 5 days

= 5 × (1 / x)

= 5 / x

We have,

• Varun does 1 / 5 of the work in 5 days.

Therefore, Equating the work done by Varun in 5 days, we get,

=5 / x

= 1 / 5

On cross-multiplying, we get,

✑5 × 5 = 1 × x

✑ 25 = x

Or, x = 25

Varun alone can do the whole work in 25 days.

____________________________________

Putting the value of x in equation (i),

we get,

• Varun alone do work in 1 day = 1/25th
• Let the work done by Amit be y

✑ Work done by Amit alone in 1 day = 1/y

Again,

[ work done by both in one day = Varun one ats work + Amit one days work]

✑ (1 / 15) = (1 / y) + (1 / 25)

✑(1 / 15) - (1 / 25) = 1 / y

L.C.M. of 15 and 25 = 75

✑ [ {1 × (75 / 15)}  - {1 × (75 / 25)} ] / 75 = 1 / y

✑{ (1 × 5) - (1 × 3) } / 75 = 1 / y

✑ (5 - 3) / 75 = 1 / y

✑ 2 / 75 = 1 / y

✑ 1 / y = 2 / 75

✑ y = 75 / 2

✑ y = 37.5

Therefore,

Total days in which Amit alone can do the Work is 37.5 days.