Question

6. An aqueous solution containing 6 g of urea in 500 mL of
solution has a density equal to 1.05. If the molar mass
of urea is 60, then the molality of solution is :
(a) 0.20
(b) 0.19 (c) 0.10 (d) 1.2.​

Answer 1

0.20

mass of solvent= 500-6=494

moles of solute=6÷60=0.1

molality=0.1/494×1000=0.20m

pls check it. i don't know that it is right or not

Answer 2

Answer: The molarity of solution is $0.2$ molar.

Explanation- Given-mass $6g$ in $500ml$ density $1.05$

Molar mass of urea of $60$

Solution- Molarity $=\frac{Number of molar}{volume in L}$

Number of moles $=\frac{mass}{molar mass}$

$=\frac{69}{60}$$=0.1$ moles

$\therefore =\frac{0.1}{0.5L} =0.2$ molar

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