6. An arithmetic sequence has a common difference of 9 and the 41st term is 25. Find the first term for this sequence?
Answers
Answered by
10
Answer:
d=9
n=41
an=25
a=?
an=a+(n-1)d
25=a+40×9
25=a+360
a=-335
Answered by
3
Given: An arithmetic sequence has a common difference of 9 and the 41st term is 25.
To find: The first term for this sequence
Solution:
In an arithmetic sequence, the Tnth term = a+(n-1)d
d=9
41st term= 25
a+(n-1)d = 25
a+ (41-1)9= 25
a+40 into 9= 25
a=335
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