Question

6. An object is placed at a distance of 50 cm from a concave lens of focal length 30 cm. Find the nature and
position of the image.​

Answer 1

Answer:

Object distance, u = -50

focal length, f = -30

from the lens formula, we know that,......

1/f = 1/v - 1/u

on putting values, we get,

1/-30 = 1/v - 1/-50

1/v = 1/-30 + 1/50

1/v = -3+5/150

1/v = 2/150

v = 75 cm.

Explanation:

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