Question

6) B) Four years ago, a father was three times as old as his daughter then was. In 8 years time, he will be twice as old as his daughter will then be. Taking
father's present age be x and daughter's present age be y, find their present ages.​

Answer 1

Step-by-step explanation:

let father's age be x

let daughter's age be y

first equation

x-4=3(y-4)

x-4=3y-12

x-3y=-8

second equation

x+8=2(y+8)

x+8=2y+16

x-2y=8

solving both the equation we get

x=40

y=16

thank u

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Answer 2

Answer:

Same answer broo.........................