Math, asked by sanjaysharma14121990, 1 year ago

6 boys complete a work in 42hrs in how may hrs 14 boys complete same work

Answers

Answered by zyan
3
by inverse proportion
6:14 is as to 42: x
P.O.M= P.O.E
⇒14*42=6X
∴X=588/6
=98

∴In 98 hrs 14 boys complete same work
hope my answer helped u!!! cheers.. 〷◠‿◠〷



sanjaysharma14121990: (Y) ty
sanjaysharma14121990: ty
sanjaysharma14121990: but if 6 boys takes 42 hrs than how can 14 boys take more times then 6 boys
zyan: dunno!! 
nikitasharma59: Hey the ans is wrong
zyan: really?
nikitasharma59: Yup
nikitasharma59: when is the takes 6 boys gust 48 hrs, why will is the take 98 hrs for 14 boys?
nikitasharma59: just
Answered by maheshsisvaishu
1
As the work is already completed by 6 boys the 14 boys need not do anything to complete it.

nikitasharma59: Lol
nikitasharma59: good one
zyan: #ROFL
nikitasharma59: What's rofl
maheshsisvaishu: It's not abt a joke as in the question is mentioned tht 14 boys had to complete the same work when the work is completed y do they work on it
nikitasharma59: Ok. But still it's kinda funny
nikitasharma59: nice logic
maheshsisvaishu: Hmm thanks..! :)
sanjaysharma14121990: they have to do that ..bcoz im saying :P
maheshsisvaishu: Watever use u r logic and thn ask them.to do d work if 6 people builders builded a building nd if ask more 14 people tht same building so thn will they break the building 
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