6. Brakes are applied to a train moving with a
velocity of 20 m/s. If the train comes to a halt
after 10 seconds, calculate the acceleration of
the train. Find the distance covered by the
train after the brakes are applied.
Answers
Answer:
→ As the train is moving with speed 20m/s
That means it's initial speed is 20m/s
→ And it is stated that it stopped after a retardation that means it's final speed is 0
u = 20m/s
v = 0
a = ?
t = 10sec
Here,
u = initial speed
v = final speed
a = retardation( negative of acceleration)
t = time
So, among 3 equations of motion we will first equation of motion to find retardation.
v = u + at
0 = 20 + (-a)(10)
10a = 20
a = 2 m/s²
So, retardation produced is 2m/s²
Now in order to find the distance travelled we will use second equation of motion as per data available in the question.
s = ut + 1/2 at²
s = 20(10) + 1/2 (2) (10)²
s = 200 + 100
s = 300m
I hopea it helps you❤️❤️
Answer:
Explanation:
As the train is moving with speed 20m/s
That means it's initial speed is 20m/s
→ And it is stated that it stopped after a retardation that means it's final speed is 0
u = 20m/s
v = 0
a = ?
t = 10sec
Here,
u = initial speed
v = final speed
a = retardation( negative of acceleration)
t = time
So, among 3 equations of motion we will first equation of motion to find retardation.
v = u + at
0 = 20 + (-a)(10)
10a = 20
a = 2 m/s²
So, retardation produced is 2m/s²
Now in order to find the distance travelled we will use second equation of motion as per data available in the question.
s = ut + 1/2 at²
s = 20(10) + 1/2 (2) (10)²
s = 200 + 100
s = 300
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