6- Calculate the mean from the following frequency distribution
(1) Secondary Data (lv)None of these
(11)Diminishing
(1) Minimum
analysis?
10-19 20-29 30-39 40-49 50-59 60-69 70-79 80-89
32
42
40
56
20
6
2
2
Answers
Answered by
0
Answer:
Explanation:
(a)
Age
Frequency (f)
Midpoint
(m)
fm
16 – 19
15
17.5
262.5
20 – 29
46
24.5
1127
30 – 39
49
34.5
1690.5
40 – 49
32
44.5
1424
50 – 59
28
54.5
1526
60 – 64
14
62
868
∑f=184
∑fm=6898
Mean
X¯¯¯=ΣfmΣf =6898184 =37.48Hence, the mean of the given distribution is 37.48
Answered by
0
Answer:
Arranging the data in ascending order.
10, 20, 42, 48, 50, 55, 60, 70, 80, 95
Here, the number of observations is even.
Median=
Size of (
N
2
)th item+Size of (
N
2
+1)th item
2
=
Size of (
10
2
)th item+Size of (
10
2
+1)th item
2
=
Size of 5th item+Size of 6th item
2
=
50+55
2
=52.5
Thus, median marks is 52.5.
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