Question

6. Check correctness of equation v=u+at by the method of dimensions.​

Answer 1

Answer:

Equation Given:

$v = u + at$

Consider LHS:

we have,

$v = \frac{d}{t}$

In dimensional analysis d = [L], t = [T],

So LHS becomes [LT^-1].

Consider RHS,

We have,

u = d/t, which gives [LT^-1]

a = v/t which gives [LT^-2], So 'at' becomes [LT^-1].

Dimensionally RHS becomes [LT^-1].

We got LHS = RHS = [LT^-1].