Math, asked by nareshsahara71, 11 months ago


6. Construct a quadrilateral ABCD in which
AB = 5 cm, BC = 5cm, A = 60°, B = 120°,
C = 90°. Measure D.
Pls explain it with steps

Answers

Answered by nehragagan515
13

Step-by-step explanation:

draw a line a b is equal to 5 cm and then at angle A draw an angle of 60 degree and at Angle B draw an angle of 120 degree we can meet at an angle so that is a construction

Answered by ns4670734
58

Step 1- A line segment of 5 cm is taken.

Step 2-Draw an angle of 60 degree at point A.

Step 3-Draw an angle of 120 degree at point B.

Step 4-Now take an arc of 5 cm and cut at point C.

Step 5-And draw 90 degree at point C .

Step 6- Join AB,BC,CD and DA.

Measure of D=?

Angle A + Angle B + Angle C + Angle D= 360 degree

so, 60 + 120 + 90 + angle D= 360 degree

270 +angle D=360 degree

Angle D=360-270=90 degree

PLEASEEEEE ...

Mark it as brainliest answer

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