Question

6. Express the following as the sum of two consecutive integers.
(1) 21sq2
(in) 13sq2
(i) 11sq2
(iv) 19sq2​

Answer 1

Step-by-step explanation:

the two consecutive number are 2 and 3

we take square of 2and3 and add their value....

2sq= 4 ; 3sq= 9

4+9=13 answer

Answer 2

the lower integer in case of a^2 will be

(a^2 - 1)/2

= (a-1)(a+1)/2

I) 21^2 = (21-1)(21+1)/2 = 20*22/2 = 220

next number = 220+1 = 221

similarly

ii) 13^2 = 84 + 85

iii) 11^2 = 60 + 61

iv) 19^2 = 180 + 181