Question

6. Find a number such that it being multiplied by 15 and 12 being added to the product will give 4692
product will give 4692.
​

Answer 1

$\mathtt{\huge{\bf{\underline{\red{Given:-}}}}}$

• A number such that it being multiplied by 15 and 12 being added to the product will give 4692.

$\mathtt{\huge{\bf{\underline{\green{To\:Find:-}}}}}$

• The produced number.

$\mathtt{\huge{\bf{\underline{\purple{Solution:-}}}}}$

Let the number be x,

• The number such that it being multiplied by 15 = 15 x

• And, 12 is added to obtained number = 15x + 12

According to the question,

The product will give 4692.

15x + 12 = 4692

➝ 15 x = 4692 - 12

➝ 15 x = 4680

➝ x = $\dfrac{4680}{15}$

➝ x = $\cancel{\dfrac{4680}{15}}$

➝ x = 312

$\mathtt{\huge{\bf{\underline{\blue{Verification:-}}}}}$

15x + 12 = 4692

➝ 15 x 312 + 12 = 4692

➝ 4680 + 12 = 4692

➝ 4692 = 4692

Hence, Verified ✔.

_________________________________________

Answer 2

Answer:

15x + 12 = 4692

➝ 15 x 312 + 12 = 4692

➝ 4680 + 12 = 4692

➝ 4692 = 4692

Hence, Verified ✔.