Question

6. Find k for which the equation kx+2y=4, 8x+ky=11 has unique solution.​

Answer 1

Answer:

Step-by-step explanation:

in unique solution a1/a2 is not equal to b1/b2

kx+2y=4

8x+ky=11

kx+2y-4=0

8x+ky-11=0

so a1=k

a2=8

b1=2

b2=k

so k/8 is not equal to 2/k

k^2 is not equal to 16

k is not equal to root 16

k is not equal to 4

hope this helped

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Answer 2

Answer:

Step-by-step explanation