Question

6. Find P(1),P(-2) for the polynomial
P(x)=(x+2)(x-2).​

Answer 1

${\huge{\boxed{\rm{ANSWER}}}}$

$\green {\colon\longrightarrow} \bf{p(x) = (x + 2)(x - 2)}$

1 ) To Find → P(1)

$\implies \bf{\: p(1) = (1 + 2)(1 - 2)} \\ \\ \implies \bf{ \: p(1) = (3)( - 1)} \\ \\ \implies \bf{ \: p(1) = \pink{- 3}}$

2 ) To Find → P(-2)

$\implies \bf{ \: p( - 2) = ( - 2 + 2)( - 2 - 2)} \\ \\ \implies \bf{ \: p( - 2) = (0)( - 4)} \\ \\ \implies \bf{ \: p( - 2) = \pink 0}$

Answer 2

Answer:

P(1)= -3

P(-2) =0

Step-by-step explanation:

(1+2)(1-2)

=3*-1

=-3

,,(-2+2)(-2-2)

=0*-4

=0