Question

6. Find the area of a rhombus whose side is 5 cm and whose altitude is 4.8 cm,
If one of its diagonals is 8 cm long, find the length of the other diagonal,
class 8
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Answer 1

Answer:

The area is 24cm squared and the length of the other diagonal is 6cm

Step-by-step explanation:

Area of rhombus = Base × Height = (1/2) ×Product of diagonals

⇒5×4.8= (1/2)×(8×x)

⇒24= (1/2)×(8×x)

⇒x = 24/4

⇒x= 6 cm

Answer 2

Since,a rhombus is also a kind of a parallelogram.

Formula of area of rhombus =Base×Altitude

Putting values, we have

Area of rhombus =5×4.8=24

Since, Area of rhombus is 24 cm².

Also,formula for area of rhombus =$\frac{1}{2}×d_1d_2$

Given,Length of one diagonal =$d_1$=8

Let length of other diagonal =$d_2$

After substituting the values, we get

$24=\frac{1}{2}×8×d_2$

$24=4×d_2$

$4×d_2=24$

$d_2=\frac{24}{4}$

$d_2=6$

Hence, length of other diagonal is 6 cm.