Question

In the given figure, AB‖ CD, <BDC = 40° and < = 75°.Find , , ​

Answer 1

Sum of four angles of a quadrilateral = 360°

Ratio in the angles = 3 : 5 : 9 : 13

Let first angle = 3x

Then second angle = 5x

Third angle = 9x

and fourth angle = 13x

∴ 3x + 5x + 9x+ 13x = 360°

⇒ 30x = 360°

⇒ x = 360∘30 = 12°

∴ First angle = 3x = 3 x 12° = 36°

Second angle = 5x = 5 x 12° = 60°

Third angle = 9x = 9 x 12° = 108°

Fourth angle = 13 x 12° = 156°

Answer 2

Answer:

Namaste mate! Here is your answer.

Angle BDC = 40°

Angle DAB = 75°

In a quadrilateral, sum of opposite angles is equal to 180°. So, simply we can find x.

Angle DAB + Angle DCB = 180°

75° + x° = 180°

x° = 180° - 75°

x° = 105°