Question

6. Find the breadth of the rectangular plot of land whose area is 660 m² and whose length is 33 m. Find
its perimeter.​

Answer 1

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Perimeter and Area of Rectangle

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The formula of perimeter and area of rectangle are explained step-by-step with solved examples.

If l denotes the length and b denotes the breadth of the rectangle, then the

Perimeter and Area of Rectangle

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● Perimeter of the rectangle = 2(l + b) units

● Length of the rectangle = P2 - b units

● Breadth of the rectangle = P2 - l units

● Area of the rectangle = l × b sq. units.

● Length of the rectangle = Ab units .

● Breadth of the rectangle = Al units

● Diagonal of the rectangle = l2+b2−−−−−√ units

Let us consider a rectangle of length 'a' units and breadth 'b' units.

Perimeter of Rectangle

Therefore, perimeter of the rectangle ABCD

= (AB + BC + CD + DA) units

= (a + b + a + b) units

= (2a + 2b) units

= 2 (a + b) units

Therefore, perimeter of the rectangle = 2 (length + breadth) units

We know that the area of the rectangle is given by

Area = length × breadth

A = a × b square units

⇒ a = Ab, i.e., length of the rectangle = Areabreadth

And b = Aa, i.e., breadth of the rectangle = Arealength

Worked-out problems on Perimeter and Area of Rectangle:

1. Find the perimeter and area of the rectangle of length 17 cm and breadth 13 cm.

Solution:

Given: length = 17 cm, breadth = 13 cm

Perimeter of rectangle = 2 (length + breadth)

= 2 (17 + 13) cm

= 2 × 30 cm

= 60 cm

We know that the area of rectangle = length × breadth

= (17 × 13) cm2

= 221 cm2

2. Find the breadth of the rectangular plot of land whose area is 660 m2 and whose length is 33 m. Find its perimeter.

Solution:

We know that the breadth of the rectangular plot = Arealength

= 660m233m

= 20 m

Therefore, the perimeter of the rectangular plot = 2 (length + breadth)

= 2(33 + 20) m

= 2 × 53 m

= 106 m