Question

6. Find the equation of the straight line whose
(i) slope is -4 and passing through (1, 2)
(ii) slope is 3
2 and passing through (5, -4)

Answer 1

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Here is your answer

Please refer to the attachment

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Answer 2

Solution :

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Equation of a line passing through

the point ( x1 , y1 ) and whose slope

is m ,

y - y1 = m( x - x1 )

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i ) Given A( 1 , 2 ) = ( x1 , y1 ) ,

slope ( m ) = -4

Required equation ,

y - 2 = ( -4 ) ( x - 1 )

=> y - 2 + 4( x - 1 ) = 0

=> y - 2 + 4x - 4 = 0

=> 4x + y - 6 = 0

ii ) Given point ( x1 , y1 ) = ( 5 , -4 )

slope ( m ) = 3/2

y - (-4) = ( 3/2) ( x - 5 )

=> 2( y + 4 ) = 3(x - 5 )

=> 2y + 8 = 3x - 15

=> 3x - 2y - 15 - 8 = 0

=> 3x - 2y - 23 = 0

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