Question

6. Find the greatest positive integer which divides 332 and 447 leaving remainder 2 in each case.

Answer 1

first subtract 2 from each number
332-2=330
447-2=445
then the h.c.f og 330 & 445
445= 330×1+115
330=115×2+0
hence the greatest num is 115

Answer 2

Hi there !!

When a no: is divides 332 and 447 , it leaves a remainder 2 in both the case .

to find the no: , follow these steps :-

1) Subtract the remainders from the numbers :-
332 - 2 = 330
447 - 2 = 445

2) HCF of 330 and 445 = greatest positive integer which divides 332 and 447 leaving remainder 2 in each case

330 = 2 . 3 . 5 . 11
445 = 5 . 89

hcf = 5


5 is the greatest positive integer which divides 332 and 447 leaving remainder 2 in each case