Question

6. Find the maximum number of students
among whom 429 mangoes and 715
oranges can be equally distributed.
Hint HCF of 429 and 715
(a) 143
(b) 153
(c) 157
(d) 163​

Answer 1

Answer:

143 I hop you like it!!!!

Answer 2

Answer:

Maximum number of students is 143.

Step-by-step explanation:

To find the maximum number of students among whom the given number of mangoes and oranges could be equally distributed we need to find the HCF of 429 mangoes and 715 oranges.

By Euclid's algorithm,

HCF(429 & 715)

715 = 429 × 1 + 286

429 = 286 × 1 + 143

286 = 143 × 2 + 0

So, 143 is the HCF of 429 and 715.

Therefore, the maximum number of students among the mangoes and oranges could be equally distributed is 143.