Question

6. Find the perimeter of a rectangle whose area is 520m' and length is 26m.


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Answer 1

Step-by-step explanation:

area= l*b

520m^2=26*b

520/26=b

20m=b

so the breadth is 20 m

and perimeter= 2(l+b)

=2(26+20)

=2*46

=92m

Answer 2

Answer:

Perimeter = 92 cm

Step-by-step explanation:

Given, Length of the rectangle (l) = 26 cm

Let its breadth be b cm

Area of the given rectangle = lb = 520 cm²

Hence, 26b = 520, b = 520/26 = 20 cm

Now, perimeter of a rectangle = 2 ( l + b )

= 2 ( 26 + 20 ) = 2 * 46 = 92 cm

Hence, its perimeter is 92 cm

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