Question

6. Find the points on the surface y= 4 + x^2 + z^2 where
the gradient is parallel i+j+k​

Answer 1

Step-by-step explanation:

the gradient of (x, y, z)and got (2x^2i,2x+1j,-1k)

and this vector must be colinear to(5,3,-1)

so, (2x^2, 2x+1, -1)

=(5,3,-1)

I get x, y, z=(1,3/2,-1)