6. Find the product.
a) (a2 + 2ab + 2bc + 2ca) (a + b - C - 1)
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Formula Used : a² + b² + 2ab = (a + b)²
In order to factorise following term, we have to break equation in two parts.
First Part : a² + b² + 2ab and Second Part : + 2bc + 2ca
First Part : (a + b)² and Second Part : 2c(a + b)
Keeping both parts together we get,
⇒ (a + b)² + 2c(a + b)
Taking (a + b) as common we get,
⇒(a + b)[ (a + b) + 2c ]
⇒ (a + b)(a + b + 2c)
Hence factorised form of a² + b² + 2ab + 2bc + 2ca into (a + b)(a + b + 2c).
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