Question

6.
Find the ratio of the number of atoms present in
16 g of O, and 32 g of O,
(1) 1:1
(2) 2:1
(3) 1:3
(4) 12
896 mL of a mixture of CO and Co, weigh 1.289
at NTP. Calculate the volume of CO, in the mixture
at NTP.
(1) 448 ml
(2) 672 ml
(3) 224 ml
(4) 500 ml
A sample of ammonium phosphate, (NH.).PO,
contains 18 moles of hydrogen atoms. The number
of moles of oxygen atoms in the sample is​

Answer 1

Answer:

Explanation:

Quantity of O = 16g (Given)

Quantity of O = 32g (Given)

Number of atom = moles x Avogadro's number x atomicity

where, Na is the Avogadro's number and atomicity is the total number of atom present in a molecule.

Thus,

Moles of O2 = 16/32

= 1/2

Moles of O3 = 32/48

=2/3

Number of atoms of O2/ Number of atoms of O3

=( 1/2 x Na x 2)/(2/3 x Na x 3)

= 1/2

Thus, the number of atoms present are in the ration 1:2.