Question

solve these linear equations . plz answer me fast ​

Answer 1

Step-by-step explanation:

(d.)

$\frac{2 - 9y}{17 - 4y} = \frac{4}{5} = > 5( 2 - 9y) = 4(17 - 4y)$

$= > 10 - 45y = 68 - 16y = > 45y -$

$16y = 10 - 68 = > 29y = - 58 = >$

$y = \frac{ - 58}{29} = - 2$

(e.)

$\frac{15}{2 - y} - \frac{5(y + 6)}{1 - 3y} = 10 = >$

$\frac{15(1 - 3y) - 5(y + 6)(2 - y)}{(2 - y)(1 - 3y)} = 10 = >$

$\frac{15 - 45y - 5(2y - {y}^{2} + 12 - 6y) }{(2 - 6y - y + 3 {y}^{2})} = 10 = >$

$15 - 45y + 20y + 5 {y}^{2} - 60 =$

$30 {y}^{2} - 70y + 20 = >$

$30 {y}^{2} - 5 {y}^{2} - 70y + 25y + 45 + 20 =$

$0 = > 25 {y}^{2} - 45y + 65 = 0 = >$

$5 {y}^{2} - 9y + 13 = 0 = >$

$y = \frac{9 + \sqrt{81 - 260} }{10} or \: \frac{9 - \sqrt{81 - 260} }{10}$

(f.)

$\frac{1}{4x} + \frac{1}{6x} = x - 7 = > \frac{3 + 2}{12x} = x - 7 = >$

$\frac{5}{12x} = x - 7 = > 12 {x}^{2} - 84x - 5 = 0$

$= > x = \frac{84 + \sqrt{ {84}^{2} + 12 \times 5 \times 4} }{24} \: or \:$

$\frac{84 - \sqrt{ {84}^{2} + 12 \times 5 \times 4 } }{24}$

Hence

x = (84+√7296)/24 or (84-√7296)/24 =>

x= (84+8√114)/24 or (84-8√114)/24 =>

x= (21+2√114)/6 or (21-2√114)/6.

Hope it helps you.

Answer 2

Hey! check the attachment above....

correction at the end-

-58/29 = -2