Question

6. Find two numbers such that the sum of thrice the first and the second
is 142, and four times the first
exceeds the second by 138.​

Answer 1

Step-by-step explanation:

X=18&Y=22.

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Answer 2

Step-by-step explanation:

Given :-

Sum of thrice the first and the second is 142, and four times the first exceeds the second by 138.

To Find :-

Two numbers

Solution :-

Let the first number be x

And the second number be y.

According to question

3x + y = 142 ……........….(i)

4x - y = 138 …….........…(ii)

On adding (i) and (ii),

⇒ 7x = 280

⇒ x = 40

Putting x value in eq (i)

⇒ 3x + y = 142

⇒ 3 × 40 + y = 142

⇒ y = (142 – 120) = 22

⇒ y = 22

Hence, the first number is 40 and the second number is 22.

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