If 2,3 are the zeroes of the polynomial 3x square minus 2k x plus 2m then find the value of k and m?
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Step-by-step explanation:
p(x) = 3x² - 2kx + 2m
p(2) = 3(2)² - 2k(2) + 2m = 12 - 4k + 2m .........equation 1
p(3) = 3(3)² - 2k(3) + 2m = 27 - 6k + 2m..........equation 2
(- 4k + 2m = -12) .........equation 1
(- 6k + 2m = -27) ..........equation 2
Eqn 1 - Eqn. 2, we get,
2k = 15
k = 15/2
Now, put k value in equation 1, we get,
- 4 x 15/2 + 2m = -12
-30 + 2m = -12
-30 + 30 + 2m = -12 +30
2m = 18
m = 9
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