Question

6 g of H2 reacts with 14gN, to form NH, till the reaction completely consumes the limiting reagent. The amount of other reactant
(in g) left are.....​

Answer 1

Answer:

Step-by-step explanation:

N2+3H2=2NH3

28gm. 6 gm. 34 gm

28 gm N2 require 6g.m

14g.m will require 3g.m H2

3 gm of H2 will remain unreacted

so N2 is limiting reagent in rxn

N2 will. decide the formation of NH3

28gm of N2 produce = 34 gm

14 g.m. will produce=17 gm NH3

limiting reagent is N2

Amount of NH3 produce =17gm