Question

6 gram of carbon was completely burnt in oxygen what would be the volume of carbon dioxide produced at the STP and how many molecules will be present

Answer 1

C+O2-->CO2
12g Co2 reacts with 32 g O2 to produce 44gCO2
6g will react with 16g O2 to give 22g CO2

44gCO2 contains 22.4L
22g CO2 contains 11.2L volume at STP

22.4L contains 6.022* 10^23
So 11.2L will contain 6.022 * 10^23/2=3.011*10^23 molecules of CO2

Hope that helps you

Answer 2

Explanation:

C+O2-->CO2

12g Co2 reacts with 32 g O2 to produce 44gCO2

6g will react with 16g O2 to give 22g CO2

44gCO2 contains 22.4L

22g CO2 contains 11.2L volume at STP

22.4L contains 6.022* 10^23

So 11.2L will contain 6.022 * 10^23/2=3.011*10^23 molecules of CO2

Hope that helps you