Question

6 gram urea is dissolved in 72 gram of water calculate mole fraction of urea and water​

Answer 1

Explanation:

N of urea =mass/M. M

So

N1=6/60=0.1mol

Then

N of water

N2=18/72=0.25

Now mole fraction X of urea is

X1=0.1/(0.25+0.1)

=0.1/0.35

=0.2857

Now for water

X2=0.25/0.35=0.714

Hope u will understand

Answer 2

Given: 6-gram urea is dissolved in 72 grams of water.

To find: We have to find the mole fraction of urea and water.

Solution:

The molecular mass of urea is 60 grams.

The given amount of urea is 6 grams.

Thus the number of moles of urea=6/60=0.1 moles.

The molecular mass of water is 18 grams.

The given amount of water is 72 grams.

Thus the number of moles of urea=72/18=4 moles.

Thus the total number of moles is 4+.1=4.1.

The mole fraction of urea is 0.1/4.1=0.024.

The mole fraction of water is 4/4.1=0.97.

Thus, the mole fraction of urea and water is 0.024 and 0.97.