Question

Please solve this question in copy

Answer 1

ANSWER:

To Solve:

• (y - 1)/3 - (y - 2)/4 = 1

Solution:

We are given that,

$\implies\dfrac{y-1}{3}-\dfrac{y-2}{4}=1$

Taking LCM,

$\implies\dfrac{4(y-1)-3(y-2)}{12}=1$

$\implies\dfrac{4y-4-3y+6}{12}=1$

$\implies\dfrac{y+2}{12}=1$

Transposing 12 to RHS,

$\implies y+2=12$

$\implies y = 12-2$

So,

$\implies\bf y = 10$

Hence, the value of y is 10.