Question

A car starts from rest and accelerates uniformly over a time of 5.21 seconds for a distance of 110 m. Determine the acceleration of the car.​

Answer 1

Given:

d = 110 m

t = 5.21 s

vi = 0 m/s

To Find:

a = ??

d = vi*t + 0.5*a*t2

110 m = (0 m/s)*(5.21 s)+ 0.5*(a)*(5.21 s)2

110 m = (13.57 s2)*a

a = (110 m)/(13.57 s2)

a = 8.10 m/ s2

Answer 2

Answer:

accleration od the car is = 8.1m/s^2

solution is given in attachment.........