6 grams of urea (NH2CONH2) dissloved in 180 grams of H20,what is molefraction of
Urea and Water ?
Answers
Answer:
Explanation:
- Mass of urea (NH₂CONH₂) = 6 gm
- Mass of water (H₂O) = 180 gm
- Molefraction of urea and water
➸ First we have to find the number of moles of urea and water
➸ Number of moles of a compund is given by,
Number of moles = Given mass/Molar mass
➸ Molar mass of NH₂CONH₂ = 14 + 2 × 1 + 12 + 16 + 14 + 2 × 1
Molar mass of NH₂CONH₂ = 14 + 2 + 12 + 16 + 14 + 2
Molar mass of NH₂CONH₂ = 60 g
➸ Molar mass of H₂O = 2 × 1 + 16
Molar mass of H₂O = 18 g
➸ Number of moles of NH₂CONH₂ = 6/60
Number of moles of NH₂CONH₂ = 0.1 moles
➸ Number of moles of H₂O = 180/18
Number of moles of H₂O = 10 moles
➸ Now mole fraction of a substance in a solution is given by,
Mole fraction = Number of moles of component/Total number of moles in the solution.
➸ Mole fraction of urea = 0.1/(0.1 + 10)
Mole fraction of urea = 0.1/10.1
Mole fraction of urea = 9.9 × 10⁻³
➸ Mole fraction of water = 10/0.1 + 10
Mole fraction of water = 10/10.1
Mole fraction of water = 0.99
➸ Number of moles of a substance is given by,
Number of moles = Given mass/Molar mass
➸ Mole fraction of a component present in a solution
Mole fraction = number of moles of component/total number of moles present in the solution.