6. How many silver coins, 1.75 cm in diameter and of thickness 2 mm, must be melted to form
a cuboid of dimensions 5.5 cm x 10 cm x 3.5 cm?
Answers
Step-by-step explanation:
Assume silver coin to be a cylinder
Dimensions of silver coin
Height= 2 mm = 0.2 cm
Diameter= 1.75 cm
Radius= Diameter/2 = 1.75/2 = 0.875 cm
Dimensions of cuboid
Length= 5.5 cm
Breadth= 10 cm
Height = 3.5 cm
Volume of one silver coin
= pi *(r^2)*h
= 3.141(0.875)(0.875)(0.2)
= 0.481 cm^3
Volume of cuboid
= l * b * h
= 5.5(10)(3.5)
= 192.5 cm^3
No. of coins required to form cuboid
= Volume of cuboid/Volume of one coin
= 192.5/0.481
= 400.207
= 401 (rounded to next nearest number)
The answer is 401
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Your ans is 400;
Number of coins = Volume of cuboid
Volume of 1 coin
Volume of cuboid
Length = 5.5 cm
Breadth = 10 cm
Height = 3.5 cm
Volume of cuboid = L*B*H
= 5.5*10*3.5
= 192.5 cm
Volume of 1 coin
coin is in the shape of cylinder with
Diameter = 1.75 cm
Radius = Diameter = 1.75 cm = 0.875 cm
2 2
= 875/1000 cm
Height = 2 mm = 2* ⅒ cm = 2/10 cm
Volume of 1 coin = πr²h
= 22/7 × (875/1000)² × 2/10
= 0.48125 cm²
Number of coins = Volume of cuboid
Volume of 1 coin
= 192.5 = 1925
0.48125 4.8125
= 19250000 = 400
48125
hence, number of coins is equal to 400;
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