Question

6) How many terms are there in GP 3, 6, 12, 24,
384:​

Answer 1

Answer:

Here a=3 and r=6/3=2. let the number of terms be n

Then,t=384=a*r^(n-1)=384=3*2^(n-1)=384=72^(n-1)=128=2^(7)

• =n-1=n=8